JAVA第十二次作业

1.for循环以i=1初始，由于i！=3，循环体内输出i，然后进行迭代语句i++，再次输出i，再次迭代后i==3，进行if语句，break跳出循环。由于输出语句是println最终输出：

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public abstract class Dongwu {
    private String name;
    private int age;
    private String xb;
    public abstract void speak();

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }

    public String getXb() {
        return xb;
    }

    public void setXb(String xb) {
        this.xb = xb;
    }

    public Dongwu() {}

    public Dongwu(String name, int age, String xb) {
        this.name = name;
        this.age = age;
        this.xb = xb;
    }

    @Override
    public String toString() {
        return "name='" + name +", age=" + age + ", xb='" + xb;
    }
}

public class Mao extends Dongwu{
    @Override
    public void speak() {
        System.out.println("猫叫");
    }

    public Mao(String name, int age, String xb) {
        super(name, age, xb);
    }

    public Mao() {
    }
}

public class Gou extends Dongwu{
    @Override
    public void speak() {
        System.out.println("狗叫");
    }

    public Gou() {
    }

    public Gou(String name, int age, String xb) {
        super(name, age, xb);
    }
}

public class Test {
    public static void main(String[] args){
        Mao m=new Mao("猫",3,"女");
        Gou g=new Gou("狗",5,"男");
        m.speak();
        g.speak();
    }
}